(12-18x)^3/(3x-2)^5

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Solution for (12-18x)^3/(3x-2)^5 equation: 


D( x )

(3*x-2)^5 = 0

(3*x-2)^5 = 0

(3*x-2)^5 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/3) U (2/3:+oo)

((12-(18*x))^3)/((3*x-2)^5) = 0

((12-18*x)^3)/((3*x-2)^5) = 0

12-18*x = 0 // - 12

-18*x = -12 // : -18

x = -12/(-18)

x = 2/3

x in { 2/3} 

x belongs to the empty set

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